Showing posts with label Dataframes. Show all posts
Showing posts with label Dataframes. Show all posts

May 18, 2020

Spark 1 vs Spark 2

 
Spark 1.xSpark 2.x
Spark Context is the entry pointSpark Session is the entry point
We need to create separately sql context, hive context if we have only SparkContext.Spark Session is enough
Spark 1.x uses compilers which uses of several function calls and CPU cycles, because of which so much unnecessary work spent on CPU cycles.Spark 2.x uses performance enhanced Tungsten engine
1X10X times faster than Spark 1.X
Spark Streaming (uses RDD batch concept)Structured Streaming (uses DataFrames/DataSet APIs)
Unified Dataset and DataFrame APIs (Dataset has more type safety, not available in Python). Now Dataframe is just an alias for Dataset of Row
Many machine learning algorithms like Gaussian Mixture Model, MaxAbsScaler, Bisecting K-Means clustering feature transformer are added to DataFrame based API and many ML algorithms added to PySpark and SparkR also.
RDD based API is going into maintenance modeDataFrame based has become the primary API now

 

Jan 10, 2020

Pandas Dataframes

# Info - lists all of our columns, also gives data types
df.info()

# Set options
pd.set_option('display.max_columns', 85)
pd.set_option('display.max_rows', 85)

# head
df.head(10)

# tail
df.tail(10)

# List all columns
df.columns

# Dataframe shape
print(df1.shape)

# Series - is a list / a column in a data frame
# A data frame is a container for multiple Series (columns)
people = {
              'first' : ['John', 'Mary', 'Linda'],
              'last' : ['Doe', 'Lee', 'Doe'],
              'email' : ['johndoe@gmail.com', 'marylee@gmail.com', 'lindadoe@gmail.com']
 }
df = pd.DataFrame(people)
type(df['email'])  # gives pandas.core.series.Series
df['email']  # gives list of emails
df.email  # gives same as above

pd.DataFrame.from_records (list of tuples)
list = [('John',30,'Bangalore'), ('Doe',25,'Chennai')] df = pd.DataFrame.from_records(list, columns=['Name', 'Age', 'City']) print(df.head(10))

df['email'] Vs df.email 
  • df['email'] is better to use over df.email
  • shape is an attribute of data frame, suppose you have a column name as shape in your DF
  • df['shape'] will give you result of shape column list 
  • df.shape will not work properly as you expect

# iloc Vs loc (Integer Location Vs Location)
# iloc (Search by position)
    df.iloc[0] # return a Series object for 0th index, access row with iloc
    df.iloc[ [0, 1] ] # returns first two rows of data, returns a Data Frame
    df.iloc[ [0, 1],  2] # returns email (2nd column) of first two rows
# loc  
(Search by label) (row_index, column_indexer)
    df.loc[0] # Same as iloc, returns Series object
    df.loc[ [ 0, 1] ] # Same as iloc, returns data frame object
    df.loc[ [ 0, 1 ], 'email' ]  # Instead of index, you can use column name
    df.loc[ [ 0, 1 ], ['email', 'last_name'] ] # Filter by multiple column names for first two rows
    df.loc[ 0, 'Hobby']  # Value of Hobby column for first row
    df.loc[ 0:5, 'Hobby:Employment']  # Values of Hobby to Employment columns for first six rows, slicing is inclusive   # see df.columns to get all the columns
    
df.loc[ df['email'] == 'abc@gmail.com',  : ]  # Rows of all with specific email (all columns)

# Get row by index
       Name  Age PinCode
0    Alex   10     500
1     Bob   12     600
2  Clarke   13     589

df.loc[2] # Gets object of Clarke by index
df1 = df.set_index('Name')  # Set Name as index, inplace=True is also there
print(df1)

             Age PinCode
Name
Alex     10     500
Bob      12     600
Clarke   13     589

df1.loc['Clarke']  # You can get the row by passing Name, since Name is the index


# Get unique values of Column (Yes/No)
df["gender"].value_counts()
Male 100
Female 200

# Unique
ll = ['John', 'Doe', 'Tom', 'Doe']
df1 = pd.Series(ll)
df2 = pd.unique(df1)
print(type(df2)) #<class 'numpy.ndarray'>
print(df2)         #['John' 'Doe' 'Tom']

# Filter
df1_link_keys = df1[df1.link_key != '']
df1_no_link_keys = df1[df1.link_key == '']

# Filter multiple/specific columns
df1 = df[['first', 'last', 'email']]  # Gives DF in return

# Filter isin
df1_subset = df1[df1.index.isin(100, 200)]

# Replace something with another
df1 = df1.replace('NULL', '')
df1 = df1.fillna('')

# Drop index
df1 = df1.drop(matched_index_list)
df1 = df1.drop(100)

# Column to list
df1_names_list = df1['name'].tolist() # column values to list
df1_index_list = df1.index.values.tolist() # index values to list

# Drop duplicates
df1.drop_duplicates(keep='last', inplace=True)  # Keep the last occurence

# Drop duplicates based on specific columns
df1.drop_duplicates(subset=['id', 'name', 'city', 'state'], keep='last', inplace=True)
df1.drop_duplicates(subset=['id', 'name', 'city', 'state'], keep='first', inplace=True)

df1 = df1.drop_duplicates(subset=['id', 'name', 'city', 'state'], keep='last')  # inplace is not true
df1 = df1.drop_duplicates(subset=['id', 'name', 'city', 'state'], keep='first') # inplace is not true

# Drop duplicates with state is empty 
# if only one record with state as empty, keep that
# If two same rows with one state is there & other state is empty, filter one with empty
s_maxes = df1.groupby(['id', 'name', 'city']).state.transform(max)
df1 = df1.loc[df1.state == s_maxes]

# Dataframe To Table
table_dtype = {
                'name': VARCHAR(),
                'city': VARCHAR(),
                'state': VARCHAR(),
                'pincode': INTEGER()
              }
df1.to_sql(con=self.db_conn, name=table_name, dtype=table_dtype,
           if_exists='replace', index=False)

# Dataframe To JSON
df.to_json('data_frame.json', orient='table')

# From Table to Dataframe
raw_data_sql = f""" select id, name, city, state
from event_raw_data
                """
df1 = pd.read_sql(raw_data_sql, con=self.db_conn, index_col="id")

# Loop Dataframe
for index, row in df1.iterrows():
print(index, row.name, row.city, row.state)

# How to subtract rows of one pandas data frame from another?
# You want to achieve df1 - df2
df1 = df1[~df1.index.isin(df2.index)]

# Read CSV
df1 = pd.read_csv('data/test.csv')
df1.shape  # (10, 5)