Python Zip

"""
input_data.txt
#########
First row contains column name
Second row contains data type
From third row, it contains student records.
How to map all the reocords using zip function?

name, age, city
varchar, int, varchar
prabhath, 32, bangalore
vamsi, 30, hyderabad
lakshmi, 30, vizag
ramesh, 50, chennai

"""

with open('input_data.txt') as input_file:
    rows = input_file.readlines()

rows = [row.strip() for row in rows]
rows = [row.split(',') for row in rows]
print rows

columns = rows[0]
data_types = rows[1]
rows = rows[2:]

for row in rows:
print '----'
for column, data_type, val in zip(columns, data_types, row):
print column.strip(), data_type.strip(), val.strip()

"""
Output:

[['name', ' age', ' city'], ['varchar', ' int', ' varchar'], ['prabhath', ' 32', ' bangalore'], ['vamsi', ' 30', ' hyderabad'], ['lakshmi', ' 30', ' vizag'], ['ramesh', ' 50', ' chennai']]
----
name varchar prabhath
age int 32
city varchar bangalore
----
name varchar vamsi
age int 30
city varchar hyderabad
----
name varchar lakshmi
age int 30
city varchar vizag
----
name varchar ramesh
age int 50
city varchar chennai
"""

Python read characters vertically in a file

with open('input_vertical.txt') as input_file:
    rows = input_file.readlines()
print rows
print '---'
rows = [row.strip() for row in rows]
print rows
##The single star * unpacks the sequence/collection into positional arguments
rows = zip(*rows)
print rows
rows = [''.join(row) for row in rows]
print rows



"""
Output:

['prabhath\n', 'test\n', 'vertical\n', 'lines']
---
['prabhath', 'test', 'vertical', 'lines']
[('p', 't', 'v', 'l'), ('r', 'e', 'e', 'i'), ('a', 's', 'r', 'n'), ('b', 't', 't', 'e')]
['ptvl', 'reei', 'asrn', 'btte']
"""